➤ Problem Link : CANDY3
👉 Hint : Simple logic using modulus
✅ C++ Solution :
#include<bits/stdc++.h>
using namespace std;
#define ll long long int
int main()
{
int t;
cin>>t;
while(t--)
{
ll n,x;
cin>>n;
ll rem=0;
for(int i=0;i<n;i++)
{
cin>>x;
rem=(rem+x%n)%n;
}
if(rem==0)
cout<<"YES"<<endl;
else
cout<<"NO"<<endl;
}
}
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I am a Member Technical at D.E. Shaw India Pvt. Ltd. CodingWithArt is a blog where you find tricks and solutions to challenging coding and development problems. I aim to build a universal tech platform for every enthusiast out there.