➤ Problem Link : CRZYSMKR
👉 Hint : edit please
✅ C++ Solution :
#include<bits/stdc++.h>
using namespace std;
#define ll long long int
int main()
{
int t;
cin>>t;
while(t--)
{
ll n;
cin>>n;
ll a=(30*n)%11;
for(ll i=a;i<a+11;i++)
{
if(i%11==0)
{
cout<<i-a<<endl;
break;
}
}
}
}
Thank you for your patience reading. If you enjoyed this post, I’d be very grateful if you’d help it spread by emailing it to a friend, or sharing it on Whatsapp or Facebook.
😇Happy Learning!!
I am a Member Technical at D.E. Shaw India Pvt. Ltd. CodingWithArt is a blog where you find tricks and solutions to challenging coding and development problems. I aim to build a universal tech platform for every enthusiast out there.